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Let me throw around my math skills... Recalling some binary math I figured that 10^2 (10 to the power of 2) may be simplified into this: 10^2 = 10x10 = 10x(2x2x2+2).
Notice all the 2's there? Here's where the left shift operator '<<' comes in handy (and it's pretty fast by the way).
So, every multiplication by 2 could be replaced by a left shift by one (in binary it's equivalent to multiplying by 2 ;) like this:
10^2 = 10<<3 + 10<<1; (by the way, this is may not be written as 10<<4! :)
So, I've replaced 10x10 by a few left shift operators. The key here is to determine how many left shifts will have to be performed for given power.
Etc.
Now, if we were programming in assembly language, maybe
(Maybe not)
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